Interesting. That's good to know. Not that I'll ever bother with RO anyway...
The best way to get around this problem is to make a solution of CaCl2 in water, and then (after it cools to room temperature) measure it's specific gravity.
Grams/Liter CaCl2 =-684.57+175.12*SG+509.45*SG^2
(where SG = specific gravity)
Example:
SG = 1.077
Grams/Liter CaCl2 =-684.57+175.12*1.077+509.45*1.077^2
Grams/L CaCl2 = 94.96
Grams/mL CaCl2 = 0.09496
If, for example you then want to add 3.5 grams of anhydrous CaCl2, then:
3.5/0.09496 = 36.86 mL required to be added
PS: If you make up 100 grams of CaCl2 prills with distilled water to a total of 1 Liter of solution, and (after it cools, wherein this blend gets right hot!) its SG is 1.077, you now know that your CaCl2 was 94.96% CaCl2 and 5.04% water. If instead the solutions SG = 1.065, then your CaCl2 is 79.76% CaCl2 and 20.24% water, etc.... Thus, this is also a great way to test the purity of your CaCl2, as it currently exists. But CaCl2 prills continually assimilate water from the air over the passing of time plus exposure to air, so it is best to just use it as a liquid solution that can no longer take on additional water.
PPS: AJ deLange deserves all credit for this method.
Lastly, for CaCl2 to be 100% pure (or anhydrous), 100 grams of it when made up to 1 L in distilled water will yield an SG of 1.081 at room temperature. I have never seen this happen. Fresh stuff, newly opened, and in my experience, is about 94-96% pure. YMMV